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We Simulated 475 Million Crash Rounds — Every Cash-Out Target Costs the Same 1%
An original data study of the crash game: 475,353,972 simulated rounds under the standard provably-fair distribution with a 1% house edge. Measured win rates matched theory at every auto-cashout target from 1.01x to 1000x, and the expected cost was the same −1% everywhere — what changes with your target is not the price but the shape of the ride: at 2x the longest losing streak was 23; at 100x it was 1,331.
Crash is the emblematic crypto-casino game: a multiplier climbs, you cash out before it crashes, and the entire strategy debate — every Reddit thread, every YouTube “method” — is about where to set the cash-out. So we measured it. 475,353,972 simulated rounds under the standard provably-fair crash distribution with a 1% house edge, one run, fixed seed, every figure below reported as it came out.
The one-line result: the cash-out target does not change what crash costs. It changes everything else.
The distribution we simulated
Major provably-fair crash implementations construct the crash point so that the probability of the round reaching your target x is proportional to 1/x, scaled by the house edge. With a 1% edge:
- P(crash point ≥ x) = 0.99/x for any target x ≥ 1
- rounds that land below the 1.01x cash-out floor are the instant busts — about 2% of all rounds
- expected value of cashing out at any target c: (0.99/c)(c−1) − (1 − 0.99/c) = −1%, independent of c
That last line is the claim every crash strategy implicitly denies, so it is the one we verified hardest.
Measured: every target, same price
Two million rounds per target (twenty million for the two rarest), fresh generator per row:
| Auto-cashout | Measured win rate | Theory (0.99/x) | Measured EV per bet | Longest losing streak |
|---|---|---|---|---|
| 1.01x | 98.0236% | 98.0198% | −0.9962% | 3 |
| 1.1x | 90.0042% | 90.0000% | −0.9954% | 7 |
| 1.5x | 66.0062% | 66.0000% | −0.9907% | 12 |
| 2x | 49.5052% | 49.5000% | −0.9896% | 23 |
| 3x | 33.0755% | 33.0000% | −0.7737% | 37 |
| 5x | 19.7944% | 19.8000% | −1.0280% | 54 |
| 10x | 9.8864% | 9.9000% | −1.1355% | 114 |
| 20x | 4.9694% | 4.9500% | −0.6130% | 237 |
| 50x | 1.9706% | 1.9800% | −1.4725% | 639 |
| 100x | 0.9880% | 0.9900% | −1.1955% | 1,331 |
| 1000x | 0.0979% | 0.0990% | −2.0550% | 8,940 |
Win rates track theory to the third decimal. The per-bet EV column scatters around −1% exactly as sampling noise predicts — the scatter widens at rare targets because a single 100x win moves the average, which is why those rows got 20 million rounds. Nothing in 475 million rounds found a target that costs less than the others.
The rightmost column is the real finding. A 2x player’s worst losing streak was 23 rounds. A 100x player’s was 1,331. Same game, same price, completely different experience — and completely different bankroll requirements.
Same 1%, opposite sessions
We then played 50,000 sessions per target: $100 bankroll, $1 flat bets, stop at broke or 2,000 rounds.
| Target | Went broke | Median rounds at bust | Still alive at 2,000 | Ever doubled the bankroll |
|---|---|---|---|---|
| 1.5x | 1.1% | 1,777 | 98.9% | 0.01% |
| 2x | 6.3% | 1,592 | 93.7% | 0.91% |
| 5x | 32.8% | 1,120 | 67.2% | 20.74% |
| 10x | 50.3% | 790 | 49.7% | 37.39% |
| 100x | 83.0% | 200 | 17.0% | 41.39% |
Read the two ends of that table together. The 1.5x grinder almost never goes broke in an evening — and almost never gets anywhere: 5 sessions in 50,000 ever saw $200. The 100x hunter doubled the bankroll at some point in 41.39% of sessions — and was broke within 2,000 rounds 83% of the time, typically after about 200. The expected loss is identical in every row. Your target choice is a choice of failure mode, not of profitability.
Martingale, measured again
Our betting-systems study already showed progression systems just repackage the house edge. Crash’s near-coin-flip 2x target is Martingale’s natural habitat, so we gave it its own run: $1 base bet, double after every loss, $100 bankroll, 500-round sessions, 100,000 sessions.
- 85.55% of sessions were wiped out — the bankroll could not cover the next doubled bet.
- The 14.45% that finished 500 rounds held a median of $352.
A $100 bankroll covers six consecutive doubled losses; the seventh needs $64 more than remains. Our 2x streams recorded losing streaks up to 23. Over 500 rounds, meeting a seven-loss streak is not bad luck — it is the arithmetic default, and the occasional $352 finishers are what keeps the system’s reputation alive.
How long until the big one
Median wait for the first appearance of each multiplier (10,000 trials each):
- ≥10x — median 7 rounds, mean 10
- ≥100x — median 69 rounds, mean 100
- ≥1000x — median 710 rounds, mean 1,013
The mean exceeding the median in every row is the signature of skew: half the time the 1000x arrives within ~710 rounds, but droughts run much longer often enough to drag the average past 1,000. “It hasn’t hit in ages, so it’s due” fails here for the same reason it fails everywhere: each round’s distribution is identical and memoryless, which our streak data demonstrates at scale.
The Aviator variant: same run at a 3% edge
Spribe’s Aviator — the most-played crash game in the world — publishes a 97% RTP rather than 99%. We re-ran the entire suite at a 3% edge (451,614,756 rounds, same seed): every cash-out target cost the same ~3% per bet (2x win rate measured 48.5099% against a 0.97/x theory of 48.5%), the streak lengths were essentially unchanged (23 at 2x, 1,331 at 100x), and Martingale’s wipeout rate rose to 88.88%. A tripled edge triples the price and changes nothing about the structure — which is the point.
Methodology
- Distribution: crash point M = 0.99/U, U uniform on (0,1) — the standard provably-fair construction via inverse transform sampling; P(M ≥ x) = 0.99/x; house edge 1%. This models the math the major crypto originals publish (roughly 99% RTP for Crash); individual operators’ exact implementations can differ in details like bet caps and floors.
- Seed: 20260821, Python
random.Random, one deterministic run per table row. No reruns, no selection. - EV rows: 2,000,000 rounds per target; 20,000,000 for 100x and 1000x.
- Sessions: $100 bankroll, $1 flat bets, stop at bankroll < $1 or 2,000 rounds; 50,000 sessions per target.
- Martingale: $1 base, double after loss, reset after win, $100 bankroll, 500-round cap, 100,000 sessions.
- Total simulated rounds: 475,353,972.
Journalists and researchers may reuse any figure on this page with attribution and a link. The comparison across operators that actually run crash games — judged on licensing, fairness documentation and payout terms rather than on the multiplier math, which is the same everywhere — is in the best crash game casinos; the game’s mechanics are in crash games explained; and where crash’s ~1% edge sits against every other casino bet is in house edge statistics.
These are expected values, not predictions of your next session — variance dominates individual outcomes, which is most of what this page measures. Nothing here makes crash profitable; the 1% is the price everywhere. Play only what you can afford to lose, where it is legal for you.
FAQ
- What is the best cash-out multiplier in crash?
- There is no best target — and that is a measured result, not an opinion. Under the standard provably-fair crash distribution with a 1% edge, the expected cost of a bet is the same −1% whether you auto-cashout at 1.1x, 2x, 10x or 100x. We verified this across 475 million simulated rounds: every target's measured win rate landed within sampling noise of theory, and every target's average return landed around −1%. The target you choose only sets the variance — how bumpy the ride is, not where it leads.
- What are the odds of reaching 2x in a crash game?
- 49.5% under a 1% house edge — we measured 49.5052% across 2 million simulated rounds. The general rule for this distribution is P(crash point ≥ x) = 0.99/x: 66% for 1.5x, 9.9% for 10x, 0.99% for 100x, 0.099% for 1000x. Our measured frequencies matched each of these within normal sampling variance.
- How long are losing streaks in crash?
- Far longer than intuition suggests, and they grow fast with the target. In our 2-million-round streams the longest losing streak was 23 rounds at a 2x auto-cashout, 54 at 5x, 114 at 10x — and 1,331 consecutive losses at a 100x target (measured over 20 million rounds). Any strategy that increases bets during a losing streak has to survive numbers like these.
- Does Martingale work in crash games?
- No, and we measured how it fails. Doubling after every loss at a 2x target, starting from $1 with a $100 bankroll, wiped out 85.55% of 100,000 simulated 500-round sessions — a $100 bankroll only covers six consecutive doubles, and our streams saw streaks up to 23. The sessions that happened to survive finished with a median of $352, which is exactly the trap: frequent small wins conceal a rare, total loss that more than pays for them.
- How often does a 100x or 1000x multiplier appear?
- A 100x or better crash point appeared with measured frequency 0.9880% (theory 0.99%) — the median wait for the first one was 69 rounds. A 1000x appeared at 0.0979% (theory 0.099%), with a median first-appearance wait of 710 rounds and a mean of 1,013. The waits are heavily skewed: the mean is larger than the median because occasional droughts run far longer.
- Can I reproduce these results?
- Yes. The distribution is crash point M = 0.99/U with U uniform on (0,1) — the standard provably-fair construction, giving P(M ≥ x) = 0.99/x and a 1% edge. The random seed is 20260821, session rules are stated in the methodology section, and the totals are reported from a single run with no reruns and no cherry-picking. Any Python environment reproduces the same figures with the same seed.